Question

3.16 as a repeating fraction?

Answer 1

`3.16161616...=313/99=3 16/99`

Explanation:

It appears that you mean `3.16161616...`,

let `x=3.16161616...`,

then `100x=316.16161616...`

Subtracting former from latter we get

`99x=313`

and `x=313/99=3 16/99`

Hence `3.16161616...=3 16/99`