What are the six trig function values of #-135#?

Question

14633 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-17T06:01:47

As below.

enter image source here

#hat (-135) = -(3pi)/4 = 2pi - (3pi)/4 = (5pi)/4#

Angle falls in III quadrant where only #tan, cot# are positive.

enter image source here

#sin ((5pi)/4) = sin (pi + (pi/4)) = - sin (pi/4) = - 1/sqrt2#

#csc ((5pi)/4) = csc (pi + (pi/4)) = - csc (pi/4) = - sqrt2#

#coc ((5pi)/4) = cos (pi + (pi/4)) = - cos (pi/4) = - 1/sqrt2#

#sec ((5pi)/4) = sec (pi + (pi/4)) = - sec (pi/4) = - sqrt2#

#tan ((5pi)/4) = tan (pi + (pi/4)) = tan (pi/4) = 1#

#cot ((5pi)/4) = cot (pi + (pi/4)) = cot (pi/4) = 1#