Question

How do you find the average velocity of the position function `s(t)=3t^2-6t` on the interval from `t=2` to `t=5`?

Answer 1

Average velocity is defined as total displacement/ total time taken for that

Given, `s=3t^2 -6t`

So,displacement in between `2s` and `5s` is `s=3[t^2]_2^5 -6[t]_2^5=3(25-4)-6(5-2)=45m`

So,average velocity =`45/(5-2)=15 ms^-1`