Question

How do you graph `y = -1/2 sin(pi/3)x`?

Answer 1

As below

Explanation:

Standard form of equation is `y = a sin(bx -c) + d`

Given : y = -(1/2) sin ((pi/3)x)#

`"Amplitude " = |a| = 1/2`

`"Period " = P = (2pi) / |b| = (2pi) / (pi/3) = 6`

`"Phase Shift " = 0`, @"Vertical Shift " = 0#

graph{-(1/2) sin ((pi/3)x) [-10, 10, -5, 5]}