How do you solve #2/x+4/x=3#?

1 Answer
Mar 18, 2018

See a solution process below:

Explanation:

First, add the fractions on the left over the common denominator:

#2/x + 4/x = 3#

#(2 + 4)/x = 3#

#6/x = 3#

Now, multiply each side by #color(red)(x)/color(blue)(3)# to solve for #x# while keeping the equation balanced:

#color(red)(x)/color(blue)(3) xx 6/x = color(red)(x)/color(blue)(3) xx 3#

#(cancel(color(red)(x))color(red)(1))/color(blue)(3) xx 6/(color(red)(cancel(color(black)(x)))1) = color(red)(x)/cancel(color(blue)(3)) xx color(blue)(cancel(color(black)(3)))#

#6/3 = x#

#2 = x#

#x = 2#