Question

How do you add `(49x-2)+(4x^2+x+7)`?

Answer 1

`4x^2 + 50x + 5`

Explanation:

Add
`(49x−2)+(4x2+x+7)`

1) Clear the parentheses by distributing the coefficients.

In this case, both parentheses have coefficients of `1`, which are not written because they are understood.

After you have cleared the parentheses by multiplying all the terms inside each set of parentheses by `1`, you get this:
`49x - 2 + 4x^2 + x + 7`

2) Group like terms
`4x^2    + 49x + x       -2 + 7`

3) Combine like terms
`4x^2 + 50x + 5` `larr` answer