Question

What is the standard form of the equation of a circle with radius 6 and center (2,4)?

Answer 1

`(x-2)^2 + (y-4)^2 = 6^2`

Explanation:

The standard equation of a circle of radius `r` and centre `(a,b)` is given by:

`(x-a)^2 + (y-b)^2 = r^2`

So a circle with radius `6` and center `(2,4)` is given by:

`(x-2)^2 + (y-4)^2 = 6^2`