How do you write an equation in standard form for a line which passes through (–2, 6) and has a slope of –1?

1 Answer
Mar 20, 2018

#x+y=4#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"the equation of a line in "color(blue)"point-slope form"# is.

#•color(white)(x)y-y_1=m(x-x_1)#

#"where m is the slope and "(x_1,y_1)" a point on the line"#

#"here "m=-1" and "(x_1,y_1)=(-2,6)#

#rArry-6=-1(x+2)larrcolor(red)"in point-slope form"#

#rArry-6=-x-2#

#rArrx+y=4larrcolor(red)"in standard form"#