How do you write an equation in standard form for a line which passes through (–2, 6) and has a slope of –1?
1 Answer
Mar 20, 2018
Explanation:
"the equation of a line in "color(blue)"standard form"the equation of a line in standard form is.
color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))
"where A is a positive integer and B, C are integers"
"the equation of a line in "color(blue)"point-slope form" is.
•color(white)(x)y-y_1=m(x-x_1)
"where m is the slope and "(x_1,y_1)" a point on the line"
"here "m=-1" and "(x_1,y_1)=(-2,6)
rArry-6=-1(x+2)larrcolor(red)"in point-slope form"
rArry-6=-x-2
rArrx+y=4larrcolor(red)"in standard form"