How do you simplify #14+ ( 1- 5) ^ { 2} \div 2#?

2 Answers
Mar 20, 2018

#22#

Explanation:

P arentheses
E xponents
M ultiplication
D ivision
A ddition
S ubtraction

#14+(1-5)^2-:2#

#=14+(-4)^2-:2#

#=14+16-:2#

#=14+8#

#=22#

Mar 20, 2018

#22#

Explanation:

Using order of operations, we will solve this equation. The easiest way to remember the order of operations is by the acronym PEDMAS:
#color(blue)"P"##"arentheses"#
#color(blue)"E"##"xponents"#
#color(blue)"D"##"ivision"# and #color(blue)"M"##"ultiplication"# (left to right)
#color(blue)"A"##"ddition"# and #color(blue)"S"##"ubtraction"# (left to right)

We have parentheses, so solve that first:
#14+(1−5)^2÷2#
#14+(-4)^2÷2#

Now exponents:
#14+(-4)^2÷2# (note: a negative number squared results in a positive number)
#14+16÷2#

Now division:
#14+16÷2#
#14 + 8#

And lastly addition:
#14 + 8 = 22#