How do you solve #5(x-3)+6=4x+3#?

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Answer 1 · 2018-03-21T18:56:12

#x = 12#

First, distribute the #5#.

#5x - 15 + 6 = 4x +3#

#5x - 9 = 4x + 3#

Simplify until you have two terms on either side of the equals sign.

#5x - 4x = 3 + 9#

Then you are left with:

#x = 12#

Optional: Plug #x# into the initial equation to confirm your answer.