How do you find the inverse of #f(x)=sqrt(3x) # and is it a function? Precalculus Functions Defined and Notation Function Composition 1 Answer 1s2s2p · Martin C. Mar 22, 2018 #x^2/3# and yes Explanation: Replace #x# by #f(x)# and the other way around and solve for #x#. #sqrt(3*f(x))=x# #3*f(x)=x^2# #f(x)=x^2/3# Since each value for #x# has one unique value for #y#, and each value for #x# has a #y# value, it is a function. Answer link Related questions What is function composition? What are some examples of function composition? What are some common mistakes students make with function composition? Is function composition associative? Is it always true that #(f@g)(x) = (g@f)(x)#? If #f(x) = x + 3# and #g(x) = 2x - 7#, what is #(f@g)(x)#? If #f(x) = x^2# and #g(x) = x + 2#, what is #(f@g)(x)#? If #f(x) = x^2# and #g(x) = x + 2#, what is #(g@f)(x)#? What is the domain of #(f@g)(x)#? What is the domain of the composite function #(g@f)(x)#? See all questions in Function Composition Impact of this question 2506 views around the world You can reuse this answer Creative Commons License