How do you solve $p (- 5 - p) = 6$ $p( - 5- p ) = 6$ ?

Question

How do you solve $p (- 5 - p) = 6$ $p( - 5- p ) = 6$ ?

2 Answers

Impact of this question

2786 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-22T14:31:14

$p = - 3 or p = - 2$ $p=-3" or "p=-2$

Explanation:

$distribute and rearrange into standard form$ $"distribute and rearrange into "color(blue)"standard form"$

$\Rightarrow - 5 p - p^{2} = 6$ $rArr-5p-p^2=6$

$\Rightarrow p^{2} + 5 p + 6 = 0 \leftarrow in standard form$ $rArrp^2+5p+6=0larrcolor(blue)"in standard form"$

$the factors of + 6 which sum to + 5 are + 3 and + 2$ $"the factors of + 6 which sum to + 5 are + 3 and + 2"$

$\Rightarrow (p + 3) (p + 2) = 0$ $rArr(p+3)(p+2)=0$

$equate each factor to zero and solve for p$ $"equate each factor to zero and solve for p"$

$p + 3 = 0 \Rightarrow p = - 3$ $p+3=0rArrp=-3$

$p + 2 = 0 \Rightarrow p = - 2$ $p+2=0rArrp=-2$

Answer 2 · 2018-03-22T14:33:02

$p = - 2 and - 3$ $p= -2 and -3$

Explanation:

$p (- 5 - p) = 6$ $p(-5-p)=6$

Using FOIL method :

$- 5 p - p^{2} = 6$ $-5p-p^2=6$

$p^{2} + 5 p + 6 = 0$ $p^2+5p+6=0$

Factorization (you can also use quadratic formula and completing square):

$(p + 3) (p + 2) = 0$ $(p+3)(p+2)=0$

$p = - 3 and - 2$ $p=-3 and -2$

Science

Math

Humanities

... and beyond

How do you solve $p (- 5 - p) = 6$ $p( - 5- p ) = 6$ ?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve p(−5−p)=6p( - 5- p ) = 6?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you solve $p (- 5 - p) = 6$ $p( - 5- p ) = 6$ ?