Given sinθ =3/5 and (π/2<θ<π), how do you find sine (2π)?

I do understand how the triangle will be in the second quadrant.

1 Answer
Mar 22, 2018

sin2theta=-24/25

Explanation:

"Do you mean "sin2theta?

As sintheta=3/5 and pi/2 < theta < pi, theta lies in second quadrant and costheta is negative.

Therefore costheta=-sqrt(1-(3/5)^2)

= -sqrt(1-9/25)=-4/5

Hence sin2theta=2sinthetacostheta=2*3/5*(-4/5)=-24/25