How do you solve $18 x^{2} - 50 = 0$ $18x^2-50=0$ ?

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How do you solve $18 x^{2} - 50 = 0$ $18x^2-50=0$ ?

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Answer 1 · 2018-03-23T11:38:03

$x = \pm \frac{5}{3}$ $x=+-5/3$

Explanation:

$add 50 to both sides$ $"add 50 to both sides"$

$\Rightarrow 18 x^{2} = 50$ $rArr18x^2=50$

$divide both sides by 18$ $"divide both sides by 18"$

$\Rightarrow x^{2} = \frac{50}{18} = \frac{25}{9}$ $rArrx^2=50/18=25/9$

$take the square root of both sides$ $color(blue)"take the square root of both sides"$

$\Rightarrow x = \pm \sqrt{\frac{25}{9}} \leftarrow note plus or minus$ $rArrx=+-sqrt(25/9)larrcolor(blue)"note plus or minus"$

$\Rightarrow x = \pm \frac{5}{3}$ $rArrx=+-5/3$

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How do you solve $18 x^{2} - 50 = 0$ $18x^2-50=0$ ?

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How do you solve 18x2−50=018x^2-50=0?

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Explanation:

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How do you solve $18 x^{2} - 50 = 0$ $18x^2-50=0$ ?