How do you find the slope of the line passing through the points (-3, -1) and (-5, -1)?

2 Answers
Mar 24, 2018

0

Explanation:

Let,
(-3,-1)= (x1,y1)
(-5,-1)= (x2,y2)

Slope(m)= (y_2-y_1)/(x_2-x_1)y2y1x2x1
= (-1-(-1))/(-5-(-3)1(1)5(3)
= 0/-202
=00

Thus the slope of the line passing through the given points is 0

Mar 24, 2018

Slope is 0

Explanation:

Points:

(x_1,y_1(x1,y1) and (x_2,y_2)(x2,y2)

(-3,-1)(3,1) and (-5,-1)(5,1)

Using the slope formula,

m=(y_2-y_1)/(x_2-x_1)m=y2y1x2x1

m=(-1-(-1))/(-5-(-3))m=1(1)5(3)

m=(-1+1)/(-1+3)m=1+11+3

m=(0)/(2)m=02

m=0m=0