How do you solve #x^2 - 6x +8 = 0 #?

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Answer 1 · 2018-03-24T04:14:28

The zeroes are 2 and 4

#x^2# - 6x + 8 = 0
#x^2# - 4x -2x + 8 = 0
x(x - 4) - 2(x - 4) = 0
(x - 2)(x - 4) = 0
x - 2 = 0 or x - 4 = 0
x = 2 or x = 4

Answer 2 · 2018-03-24T04:17:06

#x=2,4#

Solve:

#x^2-6x+8=0#

Factor.

#(x-2)(x-4)=0#

Solve for #x#.

#x-2=0#

#x=2#

#x-4=0#

#x=4#

#x=2,4#

graph{y=x^2-6x+8 [-10, 10, -5, 5]}