Question

How do you solve `1/3 z + 1/6 = 5 1/6`?

Answer 1

`z=15`

Explanation:

`1/3z+1/6 =5 1/6" "larr` change to improper fractions

`1/3z+1/6 = 31/6" "larr xx 6` to cancel the denominators

`color(blue)(6xx) 1/3z+color(blue)(6xx)1/6 = color(blue)(6xx)31/6`

`2z +1 = 31`

`" "2z =30`

`" "z = 15`