Question

How do you find the derivative of `3/(3x+3)`?

Answer 1

`dy/dx=-1/(x+1)^2`

Explanation:

`y=3/(3x+3)`
`y=1/(x+1)`

`dy/dx=d/dx (1/(x+1))`

`dy/dx=(-1/(x+1)^2)*d/dx (x+1)`

`dy/dx=(-1/(x+1)^2)*1`

`dy/dx=-1/(x+1)^2`