Question

How do you graph `y= ((sqrt 3/2)sin(x)) + (.5cos(x))`?

Answer 1

The given equation

`y= ((sqrt 3/2)sin(x)) + (.5cos(x))`

`=> y= cos(pi/6)sin(x) + sin(pi/6)cos(x))`

`=> y=1*sin(x +pi/6)`
The above relation obviously is a periodic sine function of `x`with amplitude `1` and initial phase angle `phi=pi/6`

so the graph will be as follows