How do you find the derivative of #f(y)=2y^3+4y^2#?

1 Answer
Mar 25, 2018

#f'(y)=6y^2+8y#

Explanation:

The question might seem strange because we are used to seeing functions defined in terms of some variable "#x#". But we can use any other letter, and it still works the same way.

Finding the derivative of #f(y)# with respect to #y# is exactly the same as finding the derivative of #f(x)# with respect to #x#.

#f(y)=2y^3+4y^2#

Multiply the coefficient of each term by the exponent of #y#, then lower the exponent by 1.

#f'(y)=3*2y^(3-1)+2*4y^(2-1)#

#f'(y)=6y^2+8y#