How do you add #-2x+6-(x-3)#?

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Answer 1 · 2018-03-26T00:46:50

#-3x+9#

In this question, it is important to recognize that the minus sign in front of #-(x-3)# applies to both #x# and #-3#.

Let's remove the parentheses by distributing the minus sign to the terms inside them:

#-2x+6color(red)(-)(x-3)#

#rArr-2x+6color(red)(-)xcolor(red)(-)(-3)#

#rArr-2x+6-x+3#

Now we can combine similar terms:

#rArr(-2x-x)+(6+3)#

#rArr-3x+9#

Answer 2 · 2018-03-26T00:49:51

#-3x+9#

You have to use PEMDAS and know that parentheses are always done before anything else.

So you have to distribute the #-# to #x-3#, which equals #-x+3#. Then you open the parenthesis and add or subtract like terms.

#-2x+6-x+3#

which turns into

#-3x+9#