How do you solve #x^2+3x-10=0#?
1 Answer
Mar 27, 2018
Explanation:
#"the factors of - 10 which sum to + 3 are + 5 and - 2"#
#rArr(x+5)(x-2)=0larrcolor(blue)"in factored form"#
#"equate each factor to zero and solve for x"#
#x+5=0rArrx=-5#
#x-2=0rArrx=2#