How do you solve #20=14+3(x+8)#?

2 Answers
Mar 27, 2018

#x=-6#

Explanation:

#"distribute parenthesis on the right side of the equation"#

#20=14+3x+24#

#rArr20=38+3x#

#"subtract 38 from both sides"#

#20-38=cancel(38)cancel(-38)+3x#

#rArr-18=3x#

#"divide both sides by 3"#

#(-18)/3=(cancel(3) x)/cancel(3)#

#rArrx=-6#

#color(blue)"As a check"#

Substitute this value into the right side of the equation and if equal to the left side then it is the solution.

#14+3(2)=14+6=20="left side"#

#rArrx=-6" is the solution"#

Mar 27, 2018

#x=-6#

Explanation:

Distribute the #3 #

#20=14 + 3x+24#

#20=38 +3x#

Subtract #38# from both sides

#20-38 = 3x#

#-18 = 3x#

Divide both sides by #3# to isolate #x#

# -6 = x#