Question

How do you find the domain of `1/(sqrt(17-t))`?

Answer 1

`{t in RR | -oo< t < 17}`

Explanation:

`1/sqrt(17-t)`

For real numbers the radicand ( value inside the radical ) must be greater than zero. We can't allow zero, because this would be undefined, ( division by zero ).

`:.`

`17-t>0`

`t<17`

So domain is:

`(-oo,17)`

or in set notation:

`{t in RR | -oo< t < 17}`