How do you simplify #6 times (2 ÷ 1) ÷ 1# using order of operations?

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Answer 1 · 2018-03-28T16:32:41

12

Order of Operations goes like this:

Parentheses ()
Exponents #1^2#
Multiplication/Division #*# or #/#
Addition/Subtraction #+# or #-#

Using this, we get...

#6*2/1# because we removed the parentheses

Now, we do this left to right.

#6*2=12#

#12/1=12#

Yay!