How do you simplify and find the excluded values for #9/(15a-15)#?

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Answer 1 · 2018-03-28T19:17:13

#3/(5(a-1))#

Look for things you can cancel out.

Write as: #9/(15(a-1))#

Divide top and bottom by 3

#3/(5(a-1))#

We 'are not allowed' to have a 0 as the denominator of a fraction. The official name for this condition is that it is 'undefined'.

So the excluded value is #a=1#

#3/(5(1-1))->3/(5xx0)=3/0 larr" Undefined"#