Question

What is the standard form of the equation of a circle with a center (4, 1) and a radius of 6?

Answer 1

`(x-4)^2+(y-1)^2=6^2`

Explanation:

If a circle has its centre at the point (a, b) and a radius r, then the standard form of the equation of a circle is:

`(x-a)^2+(y-b)^2=r^2`

In this case, then:

`(x-4)^2+(y-1)^2=6^2`