How do you write a polynomial function with minimum degree whose zeroes are -1, 2, 3i? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Cem Sentin Mar 29, 2018 #x^4-x^3+7x^2-9x-18# Explanation: If #3i# is zero of this polynomial, #-3i# is also zero of it. Hence #P(x)=(x-(-1))(x-2)(x-3i)(x-(-3i))# =#(x+1)(x-2)(x-3i)(x+3i)# =#(x^2-x-2)(x^2+9)# =#x^4-x^3+7x^2-9x-18# Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of #10+6i#? How do I find the complex conjugate of #14+12i#? What is the complex conjugate for the number #7-3i#? What is the complex conjugate of #3i+4#? What is the complex conjugate of #a-bi#? See all questions in Complex Conjugate Zeros Impact of this question 2697 views around the world You can reuse this answer Creative Commons License