Question

How do you solve `(x - 4)^2 = 16`?

Answer 1

`x=0,8`

Explanation:

Given: `(x-4)^2=16`

Square root both sides:

`x-4=sqrt(16)`

`x-4=+-4`

So we got: `x_1-4=4,x_2-4=-4`.

`x_1=4+4`

`=8`

`x_2=-4+4`

`=0`

`:.x\in{0,8}`