How do you solve #12=-3(2-2r)-(2r+2)# using the distributive property?

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Answer 1 · 2018-03-29T14:44:08

x=5

Distribute the first term: #-6+6r#

Distribute second term (-1): #-2r-2#

The question should now look like this: #12=-6+6r-2r-2#

Combine like terms: #12=-8+4r#

Move 4r and 12 to the other side: #-4r=-8-12#

Calculate: #-4r=-20#

Divide both sides by -4: #x=5#