How do you solve #x^2+4x - 32=0#?
1 Answer
Mar 29, 2018
Explanation:
#"the factors of - 32 which sum to + 4 are + 8 and - 4"#
#rArr(x+8)(x-4)=0#
#"equate each factor to zero and solve for x"#
#x+8=0rArrx=-8#
#x-4=0rArrx=4#
