How do you solve 3y^2+2y-1=0? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer jk.13 Mar 30, 2018 y=-1, 1/3 Explanation: 3y^2+3y-y-1=0 find two integers that ADD to 2, MULTIPLY to -3 (3*-1) 3y(y+1)-(y+1) factor out common factor (3y-1)(y+1) 3y-1 = 0 OR y+1=0 y=1/3 OR y=-1 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 4582 views around the world You can reuse this answer Creative Commons License