Question

How do you solve `2x^2 - 250x + 5000 = 0`?

Answer 1

25,100

Explanation:

`2x^2-250x+5000=0`
`rArr 2(x^2-125x+2500)=0`
`rArr x^2-125x+2500=0`
`rArr x^2-25x-100x+2500=0`
`rArr x(x-25)-100(x-25)=0`
`rArr (x-25)(x-100)=0`
`rArr (x-25)=0,(x-100)=0`
`rArr x = 25 & 100`

Answer 2

`x=25" or "x=100`

Explanation:

`"take out a "color(blue)"common factor "2`

`rArr2(x^2-125x+2500)=0`

`"the factors of + 2500 which sum to - 125 are - 25 and - 100"`

`rArr2(x-25)(x-100)=0`

`"equate each factor to zero and solve for x"`

`x-25=0rArrx=25`

`x-100=0rArrx=100`