An object with volume 6.0*10^1 m^3 and mass of 2.600*10^4 kg will have bouyancy force,in ethyl alcohol?

2 Answers
Mar 31, 2018

the force of buoyancy = mass of the bodyx g=2.6 x 10^4 kg-wt

Explanation:

the ethyl alcohol has density = 0.789 g/(ml) =789 (kg/m^3)

the volume of the body is 60 m^3 which will naturally float on the liquid with a part of it submerged in the liquid.

the volume of the displaced liquid say V1
will provide the necessary buoyant force to support the wt. of the body
therefore #V1. density . g = mass . g

where g is acceleration due to gravity.

therefore the force upward = 2.6 . 10^4 .g = 2.6. 10^5 N
here g =10 m/s^2

if one estimates volume of the liquid displaced it will come to about 32.9 m^3

it means almost half of the body will be above ethanol.

Apr 1, 2018

The buoyancy force is 2.55*10^5 N upward.

Explanation:

The density of the object is (2.6*10^4 "kg")/(60 m^3) = 433.3 "kg"/m^3.
From a table of densities, the density of ethyl alcohol is 789 "kg"/m^3, which is greater than that of the object.

Therefore the object will float. The object still has weight, a downward force, given by

m*g = 2.6*10^4 "kg"*9.8 m/s^2 = 2.55*10^5 N.

Since it is in equilibrium at the top of the ethyl alcohol, the buoyancy force must be an equal and opposite force. Therefore, the buoyancy force is 2.55*10^5 N upward.

I hope this helps,
Steve