How do you differentiate # tan (3πx²)#?
1 Answer
Apr 1, 2018
Explanation:
#"differentiate using the "color(blue)"chain rule"#
#"Given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#
#rArrd/dx(tan(3pix^2))#
#=sec^2(3pix^2)xxd/dx(3pix^2)#
#=6pixsec^2(3pix^2)#
