How do you find the derivative of #2cos^2(x)#?
1 Answer
Apr 1, 2018
Explanation:
#"differentiate using the "color(blue)"chain rule"#
#"Given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#
#y=2cos^2x=2(cosx)^2#
#rArrdy/dx=4cosx xxd/dx(cosx)#
#color(white)(rArrdy/dx)=-4sinxcosx=-2sin2x#
