How do you solve the equation #2 + (3/(x-1)) = 10#?

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Answer 1 · 2018-04-02T14:45:19

#x=11/8#

#2+(3/(x-1))#=10
#(3/(x-1))#=8
#3=8(x-1)#
#3=8x-8#
#11=8x#
#x=11/8#

Answer 2 · 2018-04-02T14:50:48

#x=1 3/8#

#2+3/(x-1)=10#
#rArr (2(x-1)+3)/(x-1)=10#
#rArr2x-2+3=10(x-1)#
#rArr2x+1=10x-10#
#rArr8x=11#
#x=11/8#
#:.x=1 3/8#