How do you determine the slope of the line passing through (3, -1) and (-2,-4)?

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Answer 1 · 2018-04-02T22:13:59

The slope is #3/5#.

Use the slope formula:

#m=(y_2-y_1)/(x_2-x_1)#,

where,

#m# is the slope, #(x_1,y_1)# is one point, and #(x_2,y_2)#.

I'm going to use #(3,-1)# as #(x_1,y_1)#, and #(-2,-4)# as #(x_2,y_2)#. The points can be reversed and the slope would be the same.

Plug in the known values and solve.

#m=(-4-(-1))/(-2-3)#

#m=-3/-5# #larr# Dividing by two negatives makes a positive.

#m=3/5#