How do you combine #(5b^2 + 3b) + (b^2 - 2b)#?

3 Answers
Apr 3, 2018

#6b^2+b#

Explanation:

#(5b^2+3b)+(b^2-2b)#
=#5b^2+3b+b^2-2b#
= #6b^2+b#

Apr 3, 2018

the answer is #5b^4-7b^3-6b^2#

Explanation:

first you have to distribute #5b^2# to everything on the other sides so:#5b^2*b^2# and #5b^2*-2b# and now do the same for #3b# so you'll have#3b*b^2# and #3b*-2b# and all together:#5b^4-10b^3+3b^3-6b^2# and now combine like terms. combine terms with the same exponents and you get your answer

Apr 3, 2018

#6b^2 +b#

Explanation:

So this is actually a really simple question.

First off you got to distribute the plus sign.

#(5b^2 + 3b) +b^2 - 2b#

Now you just add like terms.

#5b^2+b^2 +3b - 2b#

So your finally answer will be:

#6b^2 +b#