What is the derivative of #e^x/sqrt(2)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer KillerBunny Apr 3, 2018 #e^x/sqrt(2)# Explanation: Since you can write #e^x/sqrt(2)# as #e^x* 1/sqrt(2)#, and you can factor out multiplicative numbers, you have #d/dx e^x/sqrt(2) = d/dx e^x*1/sqrt(2) = 1/sqrt(2) * d/dx e^x# And since #e^x# remains unchanged when derived, we have #1/sqrt(2) * d/dx e^x = 1/sqrt(2) * e^x = e^x/sqrt(2)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1237 views around the world You can reuse this answer Creative Commons License