Question

What is the equation of the line that passes through the point (4,-5) and is parallel to 2x-5y= -10?

Answer 1

The equation of line passing through `(4,-5)` , parallal to
`2x-5y=-10` is `2x-5y=33`

Explanation:

Parallal lines have equal slopes . Therefore the equation of a line

parallal to `2x-5y=-10;(1)` is `2x-5y+c=0 ; (2)` The point

`(4,-5)` is on the line so , it will satisfy the equation (2).

`:. 2*4-5*(-5)+c=0 or 8+25+c=0 :. c=-33`

So , the equation the line is `2x-5y-33=0 or 2x-5y=33`

The equation of line passing through `(4,-5)` , parallal to

`2x-5y=-10` is `2x-5y=33` [Ans]