How do you solve the equation: #(x - 9)^2 = 1#?

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Answer 1 · 2018-04-03T12:11:12

#x=10#

=#(x-9)^2=1#

Taking square root on both sides

=#x-9=1#

=#x=10#

Hope it helps!

Answer 2 · 2018-04-03T12:11:38

#x=8,10#

Given: #(x-9)^2=1#

Square root both sides.

#x-9=sqrt(1)#

#x-9=+-1#

We got:

#x_1-9=1,x_2-9=-1#

#:.x_1=1+9,x_2=-1+9#

#x_1=10,x_2=8#

#:.x\in{8,10}#