Question

How do you find the roots, real and imaginary, of `y=(-2x-4)(x+1)+3x^2+4x` using the quadratic formula?

Answer 1

`x=2+-sqrt5`

Explanation:

When expanded,

`y=x^2-2x-4`

Using the quadratic formula,

`x=(2+-sqrt(4+16))/2`
`x=2+-sqrt20/2`
`x=2+-sqrt5`