How do you solve the system of equations $2 x + y = 2$ $2x+y=2$ and $x - 3 y = - 27$ $x-3y=-27$ ?

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Answer 1 · 2018-04-04T10:39:51

Solution: $x = - 3, y = 8$ $x= -3, y=8$

$2 x + y = 2; (1), x - 3 y = - 27; (2)$ $2x+y=2; (1), x-3y=-27 ; (2)$ . Multiplying equation (2) by

$2$ $2$ we get # 2x-6y=-54 ; (3),subtracting equation (3)

from equation (1) we get, $7y=56 :. y=56/7=8$ . Putting

$y=8$ in equation (1) we get, $2x+8=2 :. 2x= 2-8$ or

$2x= -6 :. x = -3$

Solution: $x=-3, y=8$ [Ans]

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