Which quadrant does θ lie, if sin θ > 0 and sec θ < 0? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer Somebody N. Apr 5, 2018 II Explanation: #sin(theta)>0# In quadrants I and II #sec(theta)=1/cos(theta)# #cos(theta)<0# in quadrants II and III So the quadrant where #sin(theta)>0 and 1/cos(theta)<0# is: II Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot 325^@# lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that #1+tan^2 theta = sec ^2 theta#? See all questions in Relating Trigonometric Functions Impact of this question 93258 views around the world You can reuse this answer Creative Commons License