How do you simplify #(3y)/(3y^2-6y)#?

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Answer 1 · 2018-04-06T04:15:05

#=1/(y-2)#

#(3y)/(3y^2-6y)#

#=(3y)/(3y(y-2))# factorise the denominator, HCF#=3y#

#=1/(y-2)# divide numerator and denominator by #3y#

Answer 2 · 2018-04-06T05:13:00

#1/(y-2)#

#(3y)/(3y^2-6y)#

First, we factor the bottom:
#(3y)/(3y(y-2)#

Since both the numerator and denominator are multiplied by #3y#, we can cross that out:
#(cancel(3y))/(cancel(3y)(y-2))#

So the final answer is:
#1/(y-2)#