How do you use the discriminant to determine the nature of the solutions given # 2x^2+4x+2#?

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Answer 1 · 2018-04-06T14:15:42

Below

Discriminant is given by #sqrt(b^2-4ac)#

The equation #2x^2+4x+2# is in the general form #ax^2+bx+c#

So the discriminant is

#sqrt(4^2-4times2times2)#

= #sqrt0#

=#0#

From your discriminant, you can tell it has one real double root ie at that point, it bounces off in the shape of a parabola