How do you verify the identity: #cosx cscx/cot^2x=Tanx#?
2 Answers
Apr 7, 2018
Apr 7, 2018
Explanation:
#"using the "color(blue)"trigonometric identities"#
#•color(white)(x)cscx=1/sinx" and "cotx=cosx/sinx#
#•color(white)(x)cotx=1/tanxhArrtanx=1/cotx#
#"consider the left side"#
#cosx xx(1/sinx)/(cot^2x)#
#=(cosx/sinx)/cot^2x#
#=cotx/cot^2x#
#=1/cotx=tanx="right side "rArr"verified"#