I drop a 60 g golfball from 2 m high. It rebounds to 1.5 m. How much energy is lost? c
1 Answer
Apr 8, 2018
Explanation:
Total energy before when to ball is dropped is
#"T.E"_i = "mgh" = "0.06 kg × 9.8 m/s"^2 × "2 m" = "1.176 Joule"#
Total energy after when it rebounds is
#"T.E"_f = "mgh" = "0.06 kg × 9.8 m/s"^2 × "1.5 m" = "0.882 Joule"#
Energy lost is
#Δ"T.E" = "T.E"_i - "T.E"_f = "1.176 J - 0.882 J = 0.294 J"#