Question

How do you solve `2/5=(y-26)/(y+11)`?

Answer 1

`152/3`

Explanation:

First, multiply both sides by `5(y+11)` to get rid of all denominators.

`2/cancel5 times cancel5(y+11)=(y-26)/cancel((y+11)) times 5cancel((y+11))`

Now simplify to get: `2(y+11)=5(y-26)`

Now multiply both sides out. `2y+22=5y-130`

Now place constants on the same side and the variables on the same side. `3y=152`

Now, just divide both side by 3 and you get your answer.

`y=152/3`

Now, 152 does not evenly divide by three, so we can present it as an improper fraction (`152/3`) or a mixed fraction (`50 2/3`).

Answer 2

`y = 50 2/3 ~~50.7`

Explanation:

`2/5 = (y - 26)/(y + 11)`

First, cross multiply;

`2(y + 11) = 5(y - 26)`

Secondly, eliminate the brackets;

`2y + 22 = 5y - 130`

Thirdly, collect like terms;

`2y - 5y = - 130 - 22`

`-3y = - 152`

Divide both sides by `-3`

`(-3y)/(-3) = (-152)/(-3)`

#(cancel(-3)y)/cancel(-3) = (cancel-152)/(cancel-3)#

`y = 152/3`

`y = 50 2/3 ~~50.7`

Answer 3

`y=152/3`

Explanation:

=`2/5=(y-26)/(y+11)`

=`2y+22=5y-130`

=`5y-2y=130+22`

=`3y=152`

=`y=152/3`

Hope it helps!